Question

A liquid of density $ 3000 \, \text{kg/m}^3 $ and coefficient of viscosity $ 0.1 \, \text{Pas} $ flows through a pipe with diameter $ 0.05 \, \text{m} $ with a velocity of $ 0.2 \, \text{m/s} $. The Reynolds number of the fluid is

• A. 300
• B. 400
• C. 500
• D. 600

Hint:

In fluid mechanics, the Reynolds number helps determine the flow regime, whether laminar or turbulent.

Answer 1

The Correct Option is A

The Reynolds number \( Re \) is given by the formula: \[ Re = \frac{\rho v d}{\mu} \] where \( \rho = 3000 \, \text{kg/m}^3 \), \( v = 0.2 \, \text{m/s} \), \( d = 0.05 \, \text{m} \), and \( \mu = 0.1 \, \text{Pas} \).
Substituting the values: \[ Re = \frac{3000 \times 0.2 \times 0.05}{0.1} = 300 \]
Thus, the Reynolds number is 300.