Step 1: Model the \(4\times4\) grid with coordinates \((r,c)\) where \(r=1\) at the top row and \(c=1\) at the left column. From the figure, the initially black squares are \((1,3), (2,1), (4,3)\).
Step 2: Enforce symmetry about the vertical line \(PQ\) (the line between columns 2 and 3). Reflection in \(PQ\) maps \((r,c)\mapsto (r,5-c)\). Therefore the current blacks force \((1,2), (2,4), (4,2)\) to be black.
Step 3: Enforce symmetry about the diagonal line \(MN\) (from bottom-left to top-right). Reflection in \(MN\) maps \((r,c)\mapsto (5-c,\,5-r)\). Applying this to all black squares obtained so far yields the additional required squares \((3,1)\) and \((3,4)\).
Step 4: The closure under both reflections is
\[
\{(1,2),(1,3),(2,1),(2,4),(3,1),(3,4),(4,2),(4,3)\},
\]
which contains \(8\) black squares in total. Since \(3\) were already black, the minimum number of additional squares required is \(8-3=5\). \(\boxed{5}\)