Question:

A light emitting diode (LED) is fabricated using GaAs semiconducting material whose band gap is 1.42 eV. The wavelength of light emitted from the LED is:

Updated On: Nov 23, 2024
  • 650 nm
  • 1243 nm
  • 875 nm
  • 1400 nm
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The Correct Option is C

Solution and Explanation

The wavelength of light emitted from an LED is related to its energy gap by the formula:

\( \lambda = \frac{1240}{E_g} \),

where:

  • \( \lambda \) is the wavelength in nanometers (nm),
  • \( E_g \) is the energy gap in electron volts (eV).

Substitute \( E_g = 1.42 \, \text{eV} \):

\( \lambda = \frac{1240}{1.42} \).

Perform the calculation: \( \lambda = 875 \, \text{nm} \, \text{(approximately)}. \)
Final Answer: 875 nm.

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