\(2.10 × 10^{–34}\) Js
\(-13.6+10.2=\frac{-13.6}{n^2}\)
\(⇒ \frac{13.6}{n^2} = 3.4\)
\(⇒ n = 2\)
\(⇒ Δ L = 2 \times \frac{h}{2λ} - 1 \times \frac{h}{2λ}\)
\(⇒ \frac{h}{2λ}\)
\(⇒ Δ L ≅ 1.05 \times 10^{-34} \;J\;s\)
Hence, the correct option is (B): \(1.05 × 10^{–34}\) \(J s\)
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Knowing the initial position \( x_0 \) and initial momentum \( p_0 \) is enough to determine the position and momentum at any time \( t \) for a simple harmonic motion with a given angular frequency \( \omega \).
Reason (R): The amplitude and phase can be expressed in terms of \( x_0 \) and \( p_0 \).
In the light of the above statements, choose the correct answer from the options given below:
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.