The correct answer is 42
\(Q = msΔT\)
\(\frac{dQ}{dt} = (\frac{dm }{dt})_{water}\)
\( SΔT = (\frac{dm}{dt})_{oil}C\)
\(⇒ 2 × 4.2 × 10³ × 40\)
\(= (\frac{dm}{dt})_{oil} × 8 × 10^6\)
\(⇒ (\frac{dm}{dt})_{oil} = \frac{8 × 4.2 × 10^4}{8 × 10^6} kg/minute\)
= 42 g/minute

Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
From the second law of thermodynamics, two important results are derived where the conclusions are taken together to constitute Carnot’s theorem. It may be stated in the following forms.
