The reaction is given as:
\[
A(g) \rightleftharpoons 2B(g) + C(g)
\]
At time \( t = 0 \), the pressure of A is 450 mmHg, and at time \( t = t \), the total pressure is 720 mmHg.
Let the extent of decomposition at time \( t \) be \( 2x \), so that the pressures of \( A \), \( B \), and \( C \) at time \( t \) are:
Pressure of A = \( 450 - x \)
Pressure of B = \( 2x \)
Pressure of C = \( x \)
Thus, the total pressure at time \( t \) is:
\[
P_t = P_A + P_B + P_C = (450 - x) + 2x + x = 720 \, \text{mmHg}
\]
Now, solving for \( x \):
\[
720 = 450 - x + 2x + x
\]
\[
720 = 450 + 2x
\]
\[
270 = 2x
\]
\[
x = 135
\]
The fraction of A decomposed is:
\[
\text{Fraction of A decomposed} = \frac{x}{450} = \frac{135}{450} = 0.3 = 3 \times 10^{-1}
\]
Thus, the value of \( x \) is 3.