Let the number of chairs, tables, and beds produced be denoted by \( x \), \( y \), and \( z \) respectively. We are given the following system of equations: 1. \( x + y + z = 45 \) (total furniture pieces) 2. \( z = x + 8 \) (production of beds exceeds that of chairs by 8) 3. \( x + z = 2y \) (total production of beds and chairs together is twice the production of tables) We can rewrite these equations in matrix form as: \[ \begin{bmatrix} 1 & 1 & 1 \\ 1 & 0 & -1 \\ 1 & -2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 45 \\ 8 \\ 0 \end{bmatrix} \] Now, we solve this system using matrix algebra. First, we calculate the inverse of the coefficient matrix. The coefficient matrix is: \[ A = \begin{bmatrix} 1 & 1 & 1 \\ 1 & 0 & -1 \\ 1 & -2 & 1 \end{bmatrix} \] The determinant of \( A \) is: \[ \text{det}(A) = 1 \cdot \begin{vmatrix} 0 & -1 \\ -2 & 1 \end{vmatrix} - 1 \cdot \begin{vmatrix} 1 & -1 \\ 1 & 1 \end{vmatrix} + 1 \cdot \begin{vmatrix} 1 & 0 \\ 1 & -2 \end{vmatrix} \] \[ \text{det}(A) = 1 \cdot ((0 \cdot 1) - (-1 \cdot -2)) - 1 \cdot ((1 \cdot 1) - (-1 \cdot 1)) + 1 \cdot ((1 \cdot -2) - (1 \cdot 0)) \] \[ \text{det}(A) = 1 \cdot (-2) - 1 \cdot (2) + 1 \cdot (-2) = -2 - 2 - 2 = -6 \] The inverse of \( A \) can now be computed, and the result will give us the values of \( x \), \( y \), and \( z \). Solving the system: \[ x = 17, \quad y = 14, \quad z = 18 \] Thus, the number of chairs produced is \( 17 \), the number of tables produced is \( 14 \), and the number of beds produced is \( 18 \).