A force \(F =\left(5+3 y^2\right)\) acts on a particle in the \(y\)-direction, where \(F\) is in newton and \(y\) is in meter The work done by the force during a displacement from \(y=2 m\) to \(y=5 m\) is___ \(J\).
Work done by a variable force is calculated by integrating the force with respect to displacement. Ensure the force and displacement are in the same direction.
Step 1: Recall the Formula for Work Done
The work done (\(W\)) by a variable force \(F(y)\) over a displacement from \(y_1\) to \(y_2\) is given by the integral:
\[ W = \int_{y_1}^{y_2} F(y) \, dy \]
Step 2: Substitute the Given Force and Limits
In this case, \(F(y) = 5 + 3y^2\), \(y_1 = 2 \, \text{m}\), and \(y_2 = 5 \, \text{m}\). So,
\[ W = \int_{2}^{5} (5 + 3y^2) \, dy \]
Step 3: Evaluate the Integral
\[ W = \left[ 5y + \frac{3y^3}{3} \right]_2^5 = \left[ 5y + y^3 \right]_2^5 \] \[ W = (5(5) + 5^3) - (5(2) + 2^3) \] \[ W = (25 + 125) - (10 + 8) \] \[ W = 150 - 18 = 132 \, \text{J} \]
Conclusion: The work done by the force is \(132 \, \text{J}\).
A random sample of size $5$ is taken from the distribution with density \[ f(x;\theta)= \begin{cases} \dfrac{3x^2}{\theta^3}, & 0[6pt] 0, & \text{elsewhere}, \end{cases} \] where $\theta$ is unknown. If the observations are $3,6,4,7,5$, then the maximum likelihood estimate of the $1/8$ quantile of the distribution (rounded off to one decimal place) is __________.
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
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