Given:
- \( i_2 = 200 \, \mu A \),
- \( \theta_2 = 60^\circ = \frac{\pi}{3} \, \text{radians} \).
The deflection \( \theta \) is proportional to the current \( i \). Therefore:
\(\frac{i_1}{i_2} = \frac{\theta_1}{\theta_2}.\)
For \( \theta_1 = \frac{\pi}{10} \, \text{radians} \):
\(\frac{i_1}{200} = \frac{\frac{\pi}{10}}{\frac{\pi}{3}}.\)
Simplify:
\(\frac{i_1}{200} = \frac{3}{10} \implies i_1 = 200 \times \frac{3}{10} = 60 \, \mu A.\)
The Correct answer is: 60 $\mu A$