Question:

A crystal plane of a lattice intercepts the principal axes \(\overrightarrow๐‘Ž_1, \overrightarrow๐‘Ž_2,\) and  \(\overrightarrow{a_3}\) at 3๐‘Ž1, 4๐‘Ž2, and 2๐‘Ž3, respectively. The Miller indices of the plane are:

Updated On: Jan 12, 2025
  • (436)
  • (342)
  • (634)
  • (243)
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The Correct Option is A

Solution and Explanation

To find the Miller indices of a plane, we take the reciprocal of the intercepts of the plane on the axes and reduce them to the smallest integers.

Given the intercepts at \( 3a_1, 4a_2, 2a_3 \), the reciprocals are:

  • \( h = \frac{1}{3} \)
  • \( k = \frac{1}{4} \)
  • \( l = \frac{1}{2} \)

To remove the fractions, multiply all values by 12 (the least common multiple):

  • \( h = 4 \)
  • \( k = 3 \)
  • \( l = 6 \)

Conclusion:

Thus, the Miller indices of the plane are:

\[ (436) \]

Therefore, the correct answer is (A) (436).

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