The de-Broglie wavelength is given by the relation:
\[
\lambda = \frac{h}{p}
\]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle.
If two particles — in this case, a photon and an alpha particle — have the same de-Broglie wavelength, then their momenta must be equal because:
\[
\lambda = \frac{h}{p} \Rightarrow p = \frac{h}{\lambda}
\]
Hence, both must have the same momentum.
However, since their masses and natures are different, their energy and frequency will not be the same.