Given:
Focal length, \( f = 15 \, \text{cm} \)
Object distance, \( u = -30 \, \text{cm} \) (negative for real object)
Step 1: Mirror Formula The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] where: - \( f \) is the focal length, - \( v \) is the image distance, - \( u \) is the object distance.
Step 2: Solve for Image Distance \( v \) Substitute the given values into the mirror formula: \[ \frac{1}{15} = \frac{1}{v} + \frac{1}{-30} \] \[ \frac{1}{15} = \frac{1}{v} - \frac{1}{30} \] \[ \frac{1}{v} = \frac{1}{15} + \frac{1}{30} = \frac{2 + 1}{30} = \frac{3}{30} = \frac{1}{10} \] \[ v = 10 \, \text{cm} \]
Answer: The correct answer is option (c): 60 cm.
A biconvex lens is formed by using two plano-convex lenses as shown in the figure. The refractive index and radius of curvature of surfaces are also mentioned. When an object is placed on the left side of the lens at a distance of \(30\,\text{cm}\), the magnification of the image will be: 