Question:
A compound is formed by two elements A and B. Atoms of the element B (as anion) make ccp lattice and those of element A (as cation) occupy all tetrahedral voids. The formula of the compound is
A compound is formed by two elements A and B. Atoms of the element B (as anion) make ccp lattice and those of element A (as cation) occupy all tetrahedral voids. The formula of the compound is
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In a ccp (fcc) structure, the number of tetrahedral voids is twice the number of atoms in the unit cell. If all are occupied by a different atom, use this ratio to determine the formula.
Updated On: Jun 4, 2025
- A$_4$B$_3$
- AB
- AB$_2$
- A$_2$B
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The Correct Option is D
Solution and Explanation
Step 1: Understand ccp lattice structure. In a cubic close-packed (ccp) or face-centered cubic (fcc) lattice, the number of atoms per unit cell is 4. Therefore, there are 4 atoms of B (anion) per unit cell.
Step 2: Tetrahedral voids in ccp structure. Each atom in a ccp structure contributes 2 tetrahedral voids. So, 4 B atoms result in: \[ 4 \times 2 = 8 \, \text{tetrahedral voids} \] Step 3: All tetrahedral voids are occupied by A atoms. That means there are 8 A atoms in total occupying all the voids.
Step 4: Determine empirical formula. \[ A : B = 8 : 4 = 2 : 1 \Rightarrow A_2B \]
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