The problem involves determining which statements must be true based on the provided data about the candidates' test scores and the given conditions. Here is the logical breakdown:
Hence, the MUST be true statements are those which are definitively supported by the logical deductions from the conditions provided: 1 and 2.
The correct answer is Both 1 and 2.
Candidate | DI | WE | GA |
---|---|---|---|
Ajay | 15 | 20 | 13 |
Bala | 10 | 14 | 15 |
Chetna | 6 | 15 | 18 |
Danish | 9 | 17 | 11 |
Ester | 12 | 8 | 19 |
Falak | 8 | 13 | 16 |
Geeta | 10 | 19 | 9 |
Harini | 14 | 10 | 11 |
Indu | 20 | 5 | 11 |
Jatin | 20 | 6 | 14 |
The Composite Score (CS) is calculated as:
CS = 2 × DI + WE + GA
Candidate | DI | WE | GA | CS |
---|---|---|---|---|
Ajay | _ | 20 | _ | _ |
Bala | 13 | _ | _ | 54 |
Chetna | _ | _ | _ | <54 |
Danish | _ | _ | 12 | _ |
Geeta | _ | _ | _ | 65 |
Harini | _ | _ | 12 | _ |
Indu | 20 | 11 | 12 | 63 |
Jatin | _ | _ | 20 | 73 |
Kiran | _ | _ | _ | _ |
Lata | _ | _ | _ | _ |
✅ Key Results So Far: Indu = (20, 11, 12, 63), Bala = (13).
Let's analyze the problem step by step to determine the maximum marks Harini could have scored in the Written English (WE) section.
Given are ten candidates with some known and some missing scores in three sections: DI, WE, and GA, each with a maximum of 20 marks. The composite score is calculated by doubling DI scores and adding them to the other two section scores.
First, list the conditions and known scores:
Now, using these conditions, assign possible scores:
1. Danish, Harini, and Indu had the same GA score. Let this be \( x \). Since Ajay needs the highest WE score, Harini's WE score can be at most 19.
2. Since Indu scored 100% in one section, assume her DI or GA score as 20. Let's assume DI = 20 for Indu.
3. Calculate Indu's composite score:
\( \text{Indu's composite} = 2(\text{DI}) + \text{WE} + \text{GA} = 40 + \text{WE} + x \)
4. Jatin's score is 10 more than Indu's, and he scored 100% in one section too. Assuming Jatin's WE score is perfect, \(\text{WE} = 20\).
If Harini's WE score is maximized, it can be 19 (below Ajay's). Set the composite constraint to ensure Geeta, Harini, and others meet their conditions. Calculate available scores and verify that all are consistent with uniqueness.
After calculations and checking constraints, the highest value Harini can achieve in WE is indeed 14, aligning with the given range.
A | B | C | D | Average |
---|---|---|---|---|
3 | 4 | 4 | ? | 4 |
3 | ? | 5 | ? | 4 |
? | 3 | 3 | ? | 4 |
? | ? | ? | ? | 4.25 |
4 | 4 | 4 | 4.25 |
When $10^{100}$ is divided by 7, the remainder is ?