Question:
If the marks obtained by Tahir in Thermodynamics were increased by 24% of the original marks, then what would be his new approximate percentage in Thermodynamics, when the maximum marks were 140?
If the marks obtained by Tahir in Thermodynamics were increased by 24% of the original marks, then what would be his new approximate percentage in Thermodynamics, when the maximum marks were 140?
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When calculating percentage after a mark increase, always clarify whether the increase is in actual marks or in percentage. In exams, choose the closest matching option if exact match isn't available.
Updated On: Jun 5, 2025
- 49%
- 53%
- 57%
- 41%
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The Correct Option is D
Solution and Explanation
Step 1: Identify Tahir's original marks in Thermodynamics.
From the table:
Tahir's marks in Thermodynamics = 50 \vspace{0.3cm} Step 2: Calculate 24% of Tahir's original marks.
$24%$ of $50 = \frac{24}{100} \times 50 = 12$ \vspace{0.3cm} Step 3: Add the increase to the original marks.
New marks $= 50 + 12 = 62$ \vspace{0.3cm} Step 4: Calculate the new percentage with maximum marks of 140.
Percentage $= \left(\frac{62}{140}\right) \times 100 = \frac{6200}{140} \approx 44.29%$ \vspace{0.3cm} Now compare with given options:
[6pt] % Option (A) 49% → too high
% Option (B) 53% → too high
% Option (C) 57% → too high
% Option (D) 41% → closest lower value \vspace{0.3cm} \[ \boxed{\text{(D) } 41%} \]
From the table:
Tahir's marks in Thermodynamics = 50 \vspace{0.3cm} Step 2: Calculate 24% of Tahir's original marks.
$24%$ of $50 = \frac{24}{100} \times 50 = 12$ \vspace{0.3cm} Step 3: Add the increase to the original marks.
New marks $= 50 + 12 = 62$ \vspace{0.3cm} Step 4: Calculate the new percentage with maximum marks of 140.
Percentage $= \left(\frac{62}{140}\right) \times 100 = \frac{6200}{140} \approx 44.29%$ \vspace{0.3cm} Now compare with given options:
[6pt] % Option (A) 49% → too high
% Option (B) 53% → too high
% Option (C) 57% → too high
% Option (D) 41% → closest lower value \vspace{0.3cm} \[ \boxed{\text{(D) } 41%} \]
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