Question:
A circle has radius \(7\) cm. From external point \(P\), tangent \(PT=24\) cm. If \(O\) is centre, find \(OP\).
A circle has radius \(7\) cm. From external point \(P\), tangent \(PT=24\) cm. If \(O\) is centre, find \(OP\).
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Radius to the point of tangency is perpendicular to the tangent—use Pythagoras.
Updated On: Oct 27, 2025
- \(30\) cm
- \(28\) cm
- \(25\) cm
- \(18\) cm
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The Correct Option is C
Solution and Explanation
\(OT\perp PT\). In right \(\triangle OPT\):
\[
OP^{2}=OT^{2}+PT^{2}=7^{2}+24^{2}=49+576=625\Rightarrow OP=25\ \text{cm}.
\]
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