Question:
A circle has a radius of 6 cm. Find the length of that chord which is at a distance of 4 cm from the center.
A circle has a radius of 6 cm. Find the length of that chord which is at a distance of 4 cm from the center.
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Use Pythagoras theorem to find chord length when perpendicular from center is given.
Updated On: Oct 27, 2025
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Solution and Explanation
Using the perpendicular bisector theorem:
\[ L = 2\sqrt{r^2 - d^2}. \] \[ L = 2\sqrt{6^2 - 4^2}. \] \[ = 2\sqrt{36 - 16} = 2\sqrt{20} = 2 \times 2\sqrt{5} = 4\sqrt{5} \approx 8.94 \text{ cm}. \]
\[ L = 2\sqrt{r^2 - d^2}. \] \[ L = 2\sqrt{6^2 - 4^2}. \] \[ = 2\sqrt{36 - 16} = 2\sqrt{20} = 2 \times 2\sqrt{5} = 4\sqrt{5} \approx 8.94 \text{ cm}. \]
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