A child with blood group A has father with blood group B and the mother with blood group AB. Choose the option that gives the correct genotypes of father, mother, and the child:
Blood group inheritance follows Mendelian genetics. The genotypes are determined by the alleles inherited from the parents:
IA i
(A allele and O allele).IB i
(B allele and O allele).IA IB
(both A and B alleles are expressed).Now, let's analyze the parental blood groups and their possible offspring:
IB i
.IA IB
.IA
allele. Therefore, the child’s genotype is IA i
, receiving IA
from the mother and i
from the father.Thus, the genotypes of the father, mother, and child are:
IB i
IA IB
IA i
Therefore, the correct answer is Option (A).
Simar, Tanvi, and Umara were partners in a firm sharing profits and losses in the ratio of 5 : 6 : 9. On 31st March, 2024, their Balance Sheet was as follows:
Liabilities | Amount (₹) | Assets | Amount (₹) |
Capitals: | Fixed Assets | 25,00,000 | |
Simar | 13,00,000 | Stock | 10,00,000 |
Tanvi | 12,00,000 | Debtors | 8,00,000 |
Umara | 14,00,000 | Cash | 7,00,000 |
General Reserve | 7,00,000 | Profit and Loss A/c | 2,00,000 |
Trade Payables | 6,00,000 | ||
Total | 52,00,000 | Total | 52,00,000 |
Umara died on 30th June, 2024. The partnership deed provided for the following on the death of a partner: