The correct answer is (A) : 15
\(v_y=\sqrt{2gh}=\sqrt{200}\)
\(v_{net}=\sqrt{25+200}=\sqrt{225}\)
= 15 m/s
Using kinematic equation for vertical motion: \[ v_y = \sqrt{2gh} = \sqrt{200} \] Horizontal velocity remains unchanged: \[ v_x = 5 \text{ m/s} \] Net velocity: \[ v_{\text{net}} = \sqrt{v_x^2 + v_y^2} = \sqrt{25 + 200} = 15 \text{ m/s} \]
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Linear motion is also known as the Rectilinear Motion which are of two types: