The correct answer is (A) : 15
\(v_y=\sqrt{2gh}=\sqrt{200}\)
\(v_{net}=\sqrt{25+200}=\sqrt{225}\)
= 15 m/s
Using kinematic equation for vertical motion: \[ v_y = \sqrt{2gh} = \sqrt{200} \] Horizontal velocity remains unchanged: \[ v_x = 5 \text{ m/s} \] Net velocity: \[ v_{\text{net}} = \sqrt{v_x^2 + v_y^2} = \sqrt{25 + 200} = 15 \text{ m/s} \]
The velocity (v) - time (t) plot of the motion of a body is shown below :
The acceleration (a) - time(t) graph that best suits this motion is :
A wheel of a bullock cart is rolling on a level road, as shown in the figure below. If its linear speed is v in the direction shown, which one of the following options is correct (P and Q are any highest and lowest points on the wheel, respectively) ?
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Linear motion is also known as the Rectilinear Motion which are of two types: