Question

A charged particle moving along a straight-line path enters a uniform magnetic field of \( 4 \) mT at right angles to the direction of the magnetic field. If the specific charge of the charged particle is \( 8 \times 10^7 \) C/kg, the angular velocity of the particle in the magnetic field is:

• A. \( 64 \times 10^4 \) rad \( s^{-1} \)
• B. \( 32 \times 10^4 \) rad \( s^{-1} \)
• C. \( 16 \times 10^4 \) rad \( s^{-1} \)
• D. \( 48 \times 10^4 \) rad \( s^{-1} \)

Hint:

For charged particles in a uniform magnetic field, angular velocity is given by \( \omega = \frac{qB}{m} \).

Answer 1

The Correct Option is B

Step 1: Apply Angular Velocity Formula The angular velocity is given by: \[ \omega = q B / m \] Step 2: Compute Angular Velocity \[ \omega = (8 \times 10^7) \times (4 \times 10^{-3}) \] \[ \omega = 32 \times 10^4 { rad } s^{-1} \] Thus, the correct answer is \( 32 \times 10^4 \) rad \( s^{-1} \).