Question

A colloidal solution is subjected to an electric field. The colloidal particles move toward the anode. In the coagulation of this solution using NaCl, BaCl2, and AlCl3 separately, which one is the correct order of coagulation power?

• A. NaCl \textgreater BaCl2 \textgreater AlCl3
• B. BaCl2 \textgreater AlCl3 \textgreater NaCl
• C. NaCl \textgreater AlCl3 \textgreater BaCl2
• D. AlCl3 \textgreater BaCl2 \textgreater NaCl

Hint:

Coagulation power increases with the charge of the ion; trivalent ions have the highest coagulation power.

Answer 1

The Correct Option is D

Step 1: Understanding coagulation power.
Coagulation power refers to the ability of an electrolyte to cause the aggregation or clumping of colloidal particles. The coagulation power increases with the valency of the ions and the charge they carry. Step 2: Comparing the electrolytes.
- \( \text{NaCl} \) provides Na+ ions, which are monovalent. - \( \text{BaCl}_2 \) provides Ba2+ ions, which are divalent. - \( \text{AlCl}_3 \) provides Al3+ ions, which are trivalent. Since the coagulation power increases with the charge of the ion, AlCl3 has the highest coagulation power, followed by BaCl2, and finally NaCl. Step 3: Conclusion.
The correct order of coagulation power is (4) AlCl3 \textgreater BaCl2 \textgreater NaCl.