For motion on curved roads:
• Use the formula vmax = \(\sqrt{µgr}\) for safe turning.
• Ensure all values are in consistent units for accurate results.
13.4m/s
13m/s
22.4m/s
17m/s
1. Maximum Speed on a Curved Road: - The maximum speed of a vehicle on a curved road is given by:
\[v_\text{max} = \sqrt{\mu gr},\]
where \(\mu\) is the coefficient of friction, g is the acceleration due to gravity, and r is the radius of curvature.
2. Substitute the Values: - \(\mu = 0.34\), g = 10 m/s2, r = 50 m:
\[v_\text{max} = \sqrt{0.34 \times 10 \times 50} = \sqrt{170} \approx 13 \, \text{m/s}.\]
Final Answer: \(\boxed{13 \, \text{m/s}}\)
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 