A ball is projected from the ground with a speed 15 ms1 at an angle θ with horizontal so that its range and maximum height are equal, then ‘tan θ’ will be equal to
- \(\frac{1}{4}\)
\(\frac{1}{2}\)
- 2
- 4
The Correct Option is D
Solution and Explanation
∵ tanθ=\(\frac{4H}{R}\)
⇒ tanθ = 4 × 1
⇒ tanθ = 4"
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Concepts Used:
Escape Speed
Escape speed is the minimum speed, which is required by the object to escape from the gravitational influence of a plannet. Escape speed for Earth’s surface is 11,186 m/sec.
The formula for escape speed is given below:
ve = (2GM / r)1/2
where ,
ve = Escape Velocity
G = Universal Gravitational Constant
M = Mass of the body to be escaped from
r = Distance from the centre of the mass