Question:
\( A + A.B + A.B.C + A.B.C.D \) simplifies to
\( A + A.B + A.B.C + A.B.C.D \) simplifies to
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In Boolean algebra, when a term is repeated with an AND operation, it can be simplified by factoring out the common term, reducing the complexity.
Updated On: May 5, 2025
- \( A + D \)
- \( A + C' \)
- \( A + B \)
- \( A \)
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The Correct Option is D
Solution and Explanation
Using Boolean algebra, we can simplify the expression as follows:
\[
A + A.B + A.B.C + A.B.C.D
\]
First, observe that the terms \( A.B \), \( A.B.C \), and \( A.B.C.D \) are all redundant because \( A \) is common to all terms. Therefore, the expression simplifies to:
\[
A + A.B + A.B.C + A.B.C.D = A
\]
Thus, the correct answer is option (4).
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