Question:
The Boolean function \( \sim (\sim P \land Q) \land (\sim (\sim P \land \sim Q)) \lor (P \lor R) \) is equal to the Boolean function:
The Boolean function \( \sim (\sim P \land Q) \land (\sim (\sim P \land \sim Q)) \lor (P \lor R) \) is equal to the Boolean function:
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Simplifying Boolean expressions requires using laws of Boolean algebra like De Morgan’s laws, and absorption laws.
Updated On: Jun 16, 2025
- Q
- R
- \( P \lor Q \)
- P
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The Correct Option is D
Solution and Explanation
Simplifying the given Boolean expression \( \sim (\sim P \land Q) \land (\sim (\sim P \land \sim Q)) \lor (P \lor R) \), we observe that the expression simplifies to \( P \). Using Boolean algebra, the terms involving \( \sim P \) cancel out, leaving just \( P \).
Thus, the correct answer is option (4).
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