Question:

Integrate the function: \(\frac {3x}{1+2x^4}\)

Updated On: Oct 4, 2023
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Solution and Explanation

\(Let \ \sqrt 2x^2 = t\)

\(∴ 2\sqrt2x\  dx = dt\)

\(⇒ ∫\frac {3x}{1+2x^4}\  dx = \frac {3}{2\sqrt2} ∫\frac {dt}{1+t^2}\)

\(= \frac {3}{2√2}[tan^{-1} t]+C\)

\(= \frac {3}{2√2}[tan^{-1} (\sqrt 2x^2)]+C\)

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Concepts Used:

Integrals of Some Particular Functions

There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.

Integrals of Some Particular Functions:

  • ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
  • ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
  • ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
  • ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
  • ∫1/√(a2 – x2) dx = sin-1(x/a) + C
  • ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C

These are tabulated below along with the meaning of each part.