The value of \(|X|\) is \(\underline{90.39}\).
Explanation:
Evaluating the given values we get,
\(\triangle H^{\degree}_{combustion}\) = \(\triangle H^{\degree}_{f}(HgO)-\triangle H^{\degree}_{Hg(l)}+\frac{1}{2} \triangle H^{\degree}_{f}O_2\)
\(\triangle H^{\degree}_{f}(HgO) = -151.710+61.32\)
\(\triangle H^{\degree}_{f}=90.39\)
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