Heat released by 5 kg of water when its temperature falls from 20\(^{\circ}\)C to 0\(^{\circ}\)C is
\(Q_1 =mc \Delta \theta =(5)(10^3)(20-0)=10^5 cal\)
when 2 kg ice at -20\(^{\circ}\)C comes to a temperature of 0\(^{\circ}\)C, it takes an energy
\(Q_2 =mc\Delta \theta =(2)(500)(20) =0.2 \times 10^{5}cal\)
The remaining heat \(Q=Q_1-Q_2 =0.8 \times 1^5\) cal will melt a mass m of the ice, where
\(\, \, \, \, \, \, \, \, \, \, \, m=\frac{Q}{L} =\frac{0.8 \times 10^5}{80 \times10^3}=1kg\)
So, the temperature of the mixture will be 0\(^{\circ}\)C, mass of water in it is 5 + 1 = 6 kg and mass of ice is 2 - 1 = 1 kg.
At first, the ice absorbs heat to elevate its temperature to0∘C, after which it starts melting. Let's denote mi as the initial mass of the ice, mi′ as the mass of ice that melts, and mW as the initial mass of water. According to the Law of Mixture, the heat gained by the ice equals the heat lost by the water, leading to the equation:
\(m_i \times c \times (20) + m_i' \times L = m_W \times c_W \times (20)\)
This simplifies to:
\(2 \times 0.5 \times (20) + m_i' \times 80 = 5 \times 1 \times 20\)
Which further simplifies to:
\(𝑚𝑖′=1 kg\)
Therefore, the final mass of water is the initial mass of water plus the mass of ice that melts, which equals 5+1=6 kg.
The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____
Let $ S $ denote the locus of the point of intersection of the pair of lines $$ 4x - 3y = 12\alpha,\quad 4\alpha x + 3\alpha y = 12, $$ where $ \alpha $ varies over the set of non-zero real numbers. Let $ T $ be the tangent to $ S $ passing through the points $ (p, 0) $ and $ (0, q) $, $ q > 0 $, and parallel to the line $ 4x - \frac{3}{\sqrt{2}} y = 0 $.
Then the value of $ pq $ is
Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter.
A thermodynamic system is a specific portion of matter with a definite boundary on which our attention is focused. The system boundary may be real or imaginary, fixed or deformable.
There are three types of systems:
A system undergoes a thermodynamic process when there is some energetic change within the system that is associated with changes in pressure, volume and internal energy.
There are four types of thermodynamic process that have their unique properties, and they are:
The Zeroth law of thermodynamics states that if two bodies are individually in equilibrium with a separate third body, then the first two bodies are also in thermal equilibrium with each other.
The First law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes, distinguishing three kinds of transfer of energy, as heat, as thermodynamic work, and as energy associated with matter transfer, and relating them to a function of a body's state, called internal energy.
The Second law of thermodynamics is a physical law of thermodynamics about heat and loss in its conversion.
Third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.