Question:
\(\int(\tan^2(2x)-\cot^2(2x))dx=\)
\(\int(\tan^2(2x)-\cot^2(2x))dx=\)
Updated On: May 31, 2024
- \(\frac{-1}{2}(\tan2x+\cot2x)+C\)
- 2(tan2x+cot2x)+C
- \(\frac{1}{2}(\tan2x-\cot2x)+C\)
- \(\frac{-1}{2}(\tan2x-\cot2x)+C\)
- \(\frac{1}{2}(\tan2x+\cot2x)+C\)
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The Correct Option is
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The correct option is (E) : \(\frac{1}{2}(\tan2x+\cot2x)+C\)
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