Let \(I= \int \sqrt{1+\frac{x^2}{9}}dx=\frac{1}{3}\int \sqrt{9+x^2}dx=\frac{1}{3}\int\sqrt{(3)^2+x^2}\,dx\)
It is known that,\(\int \sqrt{x^2+a^2}dx=\frac{x}{2}\sqrt{x^2+a^2}+\frac{a^2}{2}\log\mid x+\sqrt{x^2+a^2}\mid+ C\)
∴\(I=\frac{1}{3}\bigg[\frac{x}{2}\sqrt{x^2+9}+\frac{9}{2}\log\mid x+\sqrt{x^2+9}\mid\bigg]+C\)
=\(\frac{x}{6}\sqrt{x^2+9}+\frac{3}{2}\log\mid x+\sqrt{x^2+9}\mid+C\)
What is the Planning Process?
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
These are tabulated below along with the meaning of each part.