\(∫\)\(\frac {1}{9x^2+6x+5} dx\) = \(∫\frac {1}{(3x+1)^2+(2)^2}dx\)
\(Let \ (3x+1) = t\)
\(∴ 3dx = dt\)
⇒ \(∫\frac {1}{(3x+1)^2+(2)^2}dx\) \(=\) \(\frac 13 ∫\frac {1}{t^2+2^2} dt\)
\(=\frac 13 [\frac 12\ tan^{-1}(\frac t2)]+C\)
\(=\frac 16\ tan^{-1}(\frac {3x+1}{2})+C\)
Bittu and Chintu were partners in a firm sharing profit and losses in the ratio of 4 : 3. Their Balance Sheet as at 31st March, 2024 was as follows:
On 1st April, 2024, Diya was admitted in the firm for \( \frac{1}{7} \)th share in the profits on the following terms:
Prepare Revaluation Account and Partners' Capital Accounts.
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
These are tabulated below along with the meaning of each part.