Question:
Integrate the function: \(\frac {1}{\sqrt {7-6x-x^2}}\)
Integrate the function: \(\frac {1}{\sqrt {7-6x-x^2}}\)
Updated On: Oct 4, 2023
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Solution and Explanation
7-6x-x2 can be written as 7-(x2+6x+9-9).
Therefore,
7-(x2+6x+9-9)
= 16-(x2+6x+9)
= 16-(x+3)2
= (4)2-(x+3)2
∴ \(∫\)\(\frac {1}{\sqrt {7-6x-x^2}}\ dx\) = \(∫\frac {1}{\sqrt {(4)^2-(x+3)^2}} dx\)
Let x+3 = t
⇒ dx = dt
⇒ \(∫\frac {1}{\sqrt {(4)^2-(x+3)^2}} dx\) = \(∫\frac {1}{\sqrt {(4)^2-t^2}} dt\)
= \(sin^{-1}(\frac t4)+C\)
=\(sin^{-1}(\frac {x+3}4)+C\)
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- ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
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