Question:
\(\int\frac{1}{(1+cot^2x)sin^2x}dx=\)
\(\int\frac{1}{(1+cot^2x)sin^2x}dx=\)
Updated On: Jun 10, 2024
- tan-1(sinx) + C
- tan-1(cosx) + C
- cot-1(sinx) + C
- cos-1(cosx) + C
- x+C
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The Correct Option is
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The correct option is (E): x+C
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