Question:

Integrate the function: \(\frac {1}{\sqrt {1+4x^2}}\)

Updated On: Oct 4, 2023
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Solution and Explanation

\(Let\  2x = t\)

\(∴ 2dx = dt\)

\(⇒ ∫\frac {1}{\sqrt {1+4x^2}} dx\)\(\frac 12∫\frac {dt}{\sqrt {1+t^2}}\)

=\(\frac 12[log\ |t+\sqrt {t_2+1}|]+C\)            \([∫\frac {1}{\sqrt {x^2+a^2}}dt = log\ |x+\sqrt {x^2+a^2}|]\)

=\(\frac 12 \ log\ |2x+\sqrt {4x^2+1}|+C\)

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Concepts Used:

Integrals of Some Particular Functions

There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.

Integrals of Some Particular Functions:

  • ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
  • ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
  • ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
  • ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
  • ∫1/√(a2 – x2) dx = sin-1(x/a) + C
  • ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C

These are tabulated below along with the meaning of each part.