Question

\(\int\frac{1}{1+3\sin^2 x+8 \cos^2 x}\ dx=\)

• A. \(\frac{1}{6}\tan^{-1}(\frac{2\tan x}{3})+C\)
• B. \(\frac{1}{6}\tan^{-1}(2\tan x)+C\)
• C. \(6\tan^{-1}(\frac{2\tan x}{3})+C\)
• D. \(\tan^{-1}(\frac{2\tan x}{3})+C\)

Answer 1

The Correct Option is A

The correct answer is (A) : \(\frac{1}{6}\tan^{-1}(\frac{2\tan x}{3})+C\).