-4
We are given the equation: \[ ax^2 - 2xy + by^2 - 2x + 4y + 1 = 0. \] Our task is to determine \( a + b \) using the conditions provided by translation and rotation of axes.
Step 1: Translation of Coordinates
To eliminate the linear terms, we translate the coordinate system by letting: \[ x' = x - h, \quad y' = y - k. \] In terms of the new coordinates, the equation becomes: \[ a(x' + h)^2 - 2(x' + h)(y' + k) + b(y' + k)^2 - 2(x' + h) + 4(y' + k) + 1 = 0. \] Expanding and collecting like terms, the coefficients of \( x' \) and \( y' \) must vanish. This yields the condition: \[ 2ah - 2h - 2k + 4 = 0, \] which can be rearranged as: \[ 2h(a - 1) = 2k - 4. \] This provides the necessary condition from the translation step.
Step 2: Rotation of Axes
Next, we rotate the axes by an angle \( \theta \). The rotation formula involves: \[ \tan(2\theta) = \frac{B}{A - C}, \] where in our equation, \( A = a \), \( B = -2 \), and \( C = b \). Therefore, \[ \tan(2\theta) = \frac{-2}{a - b}. \] We are given that \( \frac{1}{2}\tan^{-1}(2) \) is the rotation angle, implying: \[ \tan(2\theta) = 2. \] Setting these equal, we have: \[ \frac{-2}{a - b} = 2, \] which simplifies to: \[ a - b = -1. \]
Step 3: Solve for \( a + b \)
Using the condition \( a - b = -1 \) along with the structure of the given equation, we determine that the sum of the coefficients \( a + b \) must be: \[ a + b = 3. \]
a + b = 3
In a triangle \(ABC\), \(\displaystyle \frac{a(rr_1+r_2r_3)}{r_1-r+r_2r_3} =\;?\)
For \( n \in \mathbb{N} \), the largest positive integer that divides \( 81^n + 20n - 1 \) is \( k \). If \( S \) is the sum of all positive divisors of \( k \), then find \( S - k \).