0.05M CuSO$_4$ when treated with 0.01M K$_2$Cr$_2$O$_7$ gives green colour solution of Cu$_2$Cr$_2$O$_7$. The \[ \text{[SPM : Semi Permeable Membrane]} \]\(K_2Cr_2O_7\) \(CuSO_4\) Side X SPM Side Y
Due to osmosis:
| \(K_2Cr_2O_7\) | \(CuSO_4\) | |
| Side X | SPM | Side Y |
Due to osmosis:
- Green colour formation observed on side Y.
- Green colour formation observed on side X.
- Molarity of\(K_2Cr_2O_7\)solution is lowered.
- Molarity of\(CuSO_4\)solution is lowered.
The Correct Option is D
Solution and Explanation
Due to osmosis, the solvent molecules from side Y (CuSO4) diffuse across the semi-permeable membrane (SPM) into side X (K2Cr2O7). This dilution effect causes the molarity of the CuSO4 solution (side Y) to decrease over time.
- CuSO4 reacts with K2Cr2O7, forming Cu2Cr2O7, which is responsible for the green color.
- The green color is observed due to the formation of Cu2Cr2O7, but the key change is in the molarity of the CuSO4 solution on side Y, which decreases as the solvent diffuses.
Thus the correct answer is Option 4.
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