| \(K_2Cr_2O_7\) | \(CuSO_4\) | |
| Side X | SPM | Side Y |
To solve this problem, we need to understand the concept of osmosis and how it affects the molarity of solutions separated by a semipermeable membrane (SPM).
In the given scenario, we have the following setup:
| \(K_2Cr_2O_7\) | \(CuSO_4\) | |
| Side X | SPM | Side Y |
In this arrangement, \(K_2Cr_2O_7\) is on Side X and \(CuSO_4\) is on Side Y. Osmosis refers to the movement of solvent molecules through a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration.
Now, let's analyze the options:
Since the solutions are separated by a semipermeable membrane, only the solvent (typically water) can move to equalize solute concentrations, not the solute itself. Therefore, any change in molarity due to osmosis would typically be a result of water moving from the side with lower solute concentration to the side with higher solute concentration, making the latter solution more dilute.
In this situation, osmosis will cause the water to move from the \(K_2Cr_2O_7\) side (Side X) to the \(CuSO_4\) side (Side Y) because the \(CuSO_4\) solution is involved in forming the green complex \(Cu_2Cr_2O_7\), thereby reducing its effective concentration.
Thus, the molarity of the \(CuSO_4\) solution is lowered as water moves into Side Y to equalize concentration due to osmosis.
Therefore, the correct option is:
Molarity of \(CuSO_4\) solution is lowered.
Due to osmosis, the solvent molecules from side Y (CuSO4) diffuse across the semi-permeable membrane (SPM) into side X (K2Cr2O7). This dilution effect causes the molarity of the CuSO4 solution (side Y) to decrease over time.
Thus the correct answer is Option 4.

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.