An aromatic compound ‘A’ with molecular formula C8H8O gives positive 2,4-DNP test. It gives yellow precipitate of compound ‘B’ on treatment with sodium hypoiodite. Compound ‘A’ does not react with Tollen’s or Fehling’s reagent; on drastic oxidation with KMnO4 it forms a carboxylic acid ‘C’. Elucidate the structures of A, B, and C. Also give their IUPAC names.
Give explanation for each of the following observations:
(a) With the same d-orbital configuration (d4), Mn3+ ion is an oxidizing agent whereas Cr2+ ion is a reducing agent.
(b) Actinoid contraction is greater from element to element than that among lanthanoids.
(c) Transition metals form a large number of interstitial compounds with H, B, C, and N.
The reaction between A2 (g) and B2 (g) was carried out in a sealed isothermal container. The rate law for the reaction was found to be:
Rate = \( k[\text{A}_2][\text{B}_2] \)
If 1 mole of A2 (g) was added to the reaction chamber and the temperature was kept constant, then predict the change in rate of the reaction and the rate constant.
Out of Ti3+, Cr3+, Fe2+ and Ni2+ ions, the one which is the most stable ion in aqueous solution is:
Name the type of isomerism exhibited and draw isomers:
(I) [Co(NH3)6][Cr(CN)6]
(II) [Co(en)3]3+
(III) [Co(NH3)3(NO2)3]
(a) Mn3+ is an oxidizing agent, whereas Cr2+ is a reducing agent (both d4 configuration).
(b) Actinoid contraction is greater than lanthanoid contraction.
(c) Transition metals form interstitial compounds with H, B, C, N.
(i) \( \text{CH}_3\text{CH} = \text{CH}_2 \) \( \xrightarrow{\text{HBr, Peroxide}} \) ‘A’ \( \xrightarrow{\text{aq. KOH}} \) ‘B’
(ii) \( \text{CH}_3\text{CH}_2\text{CH(Cl)CH}_3 \) \( \xrightarrow{\text{alc. KOH}, \Delta} \) ‘A’ \( \xrightarrow{\text{HBr}} \) ‘B’
(iii) ‘A’ \( \xrightarrow{\text{Mg}} \) \( \text{CH}_3\text{CH}_2\text{CH}_2\text{MgCl} \) \( \xrightarrow{\text{H}_2\text{O, H}^+} \) ‘B’ (Main product)