Two charges +q and -q, each 1 $\mu$C are arranged as shown in the figure. If x = 2 cm and y = 3 cm then potential difference ($V_A - V_B$) is
In the circuit, $ E_1 = E_2 = E_3 = 2 \, \text{V} $ and $ R_1 = R_2 = 4 \, \Omega $. Then the current flowing through $ E_2 $ is:
Switch $ S $ is closed. Now the switch is opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant 3. The ratio of total electrostatic energy stored in the capacitors before and after the introduction of the dielectric is:
The resultant resistance between $ A $ and $ B $ in the given figure is:
In the given pressure ($ P $) - absolute temperature ($ T $) graph of an ideal gas, the relation between volumes $ V_1, V_2, V_3, $ and $ V_4 $ is: