Consider the following cell at 298 K:
\[
{Mg(s)} | {Mg}^{2+}(x M) || {Zn}^{2+}(y M) | {Zn(s)}
\]
The cell reaction reached the equilibrium state. What is the value of \(\log \frac{[{Mg}^{2+}]}{[{Zn}^{2+}]}\)?
Given:
\[
E^\circ_{{Mg}^{2+}/{Mg}} = -2.36\, V; E^\circ_{{Zn}^{2+}/{Zn}} = -0.76\, V; \frac{2.303 RT}{F} = 0.06\, V
\]