Question

How many molecules are present in 4.4 grams of CO\(_2\)? 
(Molar mass of CO\(_2\) = 44 g/mol, Avogadro's number = \(6.022 \times 10^{23}\))

• A. \(6.022 \times 10^{23}\)
• B. \(3.011 \times 10^{23}\)
• C. \(6.022 \times 10^{22}\)
• D. \(1.204 \times 10^{23}\)

Hint:

Moles = mass / molar mass; molecules = moles \(\times\) Avogadro's number.

Answer 1

The Correct Option is B

- Calculate the number of moles of CO\(_2\) using: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{4.4\, \text{g}}{44\, \text{g/mol}} = 0.1\, \text{mol} \] - Number of molecules = moles \(\times\) Avogadro's number \[ = 0.1 \times 6.022 \times 10^{23} = 6.022 \times 10^{22} \] - Check options: \(6.022 \times 10^{22}\) corresponds to option (C). 
Note: The correct calculation gives (C), but if your options list (B) \(3.011 \times 10^{23}\), that corresponds to 0.5 mol. Since 4.4 g CO\(_2\) is 0.1 mol, answer is (C). 
Answer: \(\boxed{\text{C}}\)