A parabola has the origin as its focus and the line x=2 x = 2 x=2 as the directrix. Then the vertex of the parabola is at:
The relationship between a a a and b b b so that the function f(x) f(x) f(x) defined by
is continuous at x=3 x = 3 x=3, is:
If the system of linear equations x+ky+3z=0,3x+ky−2z=0,2x+4y−3z=0 x + ky + 3z = 0, \quad 3x + ky - 2z = 0, \quad 2x + 4y - 3z = 0 x+ky+3z=0,3x+ky−2z=0,2x+4y−3z=0 has a non-zero solution (x,y,z) (x, y, z) (x,y,z), then xzy2 \frac{xz}{y^2} y2xz is equal to:
The equation of the hyperbola with vertices at
is:
The local minimum value of the function f(x)=3+∣x∣,x∈R f(x) = 3 + |x|, \quad x \in \mathbb{R} f(x)=3+∣x∣,x∈R is: