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VITEEE
List of top Questions asked in VITEEE
Caffeine has a molecular weight of
194
u
194\, u
194
u
. If it contains
28.9
%
28.9\%
28.9%
by mass of nitrogen, number of atom of nitrogen in one molecule of caffeine is
VITEEE - 2015
VITEEE
Chemistry
Some basic concepts of chemistry
If a line segment OP makes angles of
π
4
\frac{\pi}{4}
4
π
and
π
3
\frac{\pi }{3}
3
π
with X-axis and Y-axis, respectively. Then, the direction cosines are
VITEEE - 2015
VITEEE
Mathematics
Three Dimensional Geometry
If
(
2
,
7
,
3
)
(2, 7, 3)
(
2
,
7
,
3
)
is one end of a diameter of the sphere
x
2
+
y
2
+
z
2
−
6
x
−
12
y
−
2
z
+
20
=
0
x^2 + y^2 + z^2 - 6\,x -12\,y -2\,z + 20 = 0
x
2
+
y
2
+
z
2
−
6
x
−
12
y
−
2
z
+
20
=
0
, then the coordinates of the other end of the diameter are
VITEEE - 2015
VITEEE
Mathematics
Three Dimensional Geometry
A current of
2
A
2\,A
2
A
is flowing in the sides of an equilateral triangle of side
9
c
m
9\, cm
9
c
m
. The magnetic field at the centroid of the triangle is
VITEEE - 2015
VITEEE
Physics
Magnetic Field Due To A Current Element, Biot-Savart Law
A galvanometer with a scale divided into
100
100
100
equal divisions has a current sensitivity of
10
10
10
divisions per milliampere and a voltage sensitivity of
2
2
2
divisions per millivolt. The galvanometer resistance will be
VITEEE - 2015
VITEEE
Physics
Electrical Instruments
X
C
l
2
(
e
x
c
e
s
s
)
+
Y
C
l
2
X
C
l
4
+
Y
↓
X Cl _{2}( excess )+Y Cl _{2} X Cl _{4}+Y \downarrow
XC
l
2
(
e
x
cess
)
+
Y
C
l
2
XC
l
4
+
Y
↓
Y
O
−
>
[
Δ
]
[
>
40
0
∘
C
]
1
2
O
2
+
Y
Y O {->[{\Delta}][{>400^{\circ} C }]} \frac{1}{2} O _{2}+Y
Y
O
−
>
[
Δ
]
[
>
40
0
∘
C
]
2
1
O
2
+
Y
Ore of Y would be ,
VITEEE - 2015
VITEEE
Chemistry
Chlorine
Which one of the following is a case of negative adsorption?
VITEEE - 2015
VITEEE
Chemistry
Adsorption
With excess of water, both
P
2
O
5
P_{2}O_{5}
P
2
O
5
and
P
C
l
5
PCl_{5}
PC
l
5
give
VITEEE - 2015
VITEEE
Chemistry
Group 15 Elements
Which of the following reactions is used to prepare isobutane ?
VITEEE - 2015
VITEEE
Chemistry
Chemical Reactions
Two sources of equal emf are connected to a resistance
R
R
R
. The internal resistance of these sources are
r
1
r_1
r
1
and
r
2
(
r
1
>
r
2
)
r_2 (r_1 > r_2 )
r
2
(
r
1
>
r
2
)
. If the potential difference across the source having internal resistance
r
2
r_2
r
2
is zero, then
VITEEE - 2015
VITEEE
Physics
Magnetic Field
Two points masses,
m
m
m
each carrying charges
−
q
-q
−
q
and
+
q
+q
+
q
are attached to the ends of a mass less rigid non-conducting wire of length
′
L
′
'L'
′
L
′
. When this arrangement is placed in a uniform electric field, then it deflects through an angle
i
i
i
. The minimum time needed by rod to align itself along the field is
VITEEE - 2015
VITEEE
Physics
Electric Dipole
Two polaroids are kept crossed to each other. If one of them is rotated an angle
6
0
∘
60^{\circ}
6
0
∘
, the percentage of incident light now transmitted through the system is
VITEEE - 2015
VITEEE
Physics
Polarisation
If
N
N
N
is a set of natural numbers, then under binary operation
a
?
b
=
a
+
b
,
(
N
,
?
)
a ?b =a + b, (N, ?)
a
?
b
=
a
+
b
,
(
N
,
?)
is
VITEEE - 2015
VITEEE
Mathematics
Relations and functions
The two lines
x
=
m
y
+
n
,
z
=
p
y
+
q
x = my + n, z = py + q
x
=
m
y
+
n
,
z
=
p
y
+
q
and
x
=
m
′
y
+
n
′
,
z
=
p
′
y
+
q
′
x = m'y + n',\, z = p'y + q'
x
=
m
′
y
+
n
′
,
z
=
p
′
y
+
q
′
are perpendicular to each other, if
VITEEE - 2015
VITEEE
Mathematics
Three Dimensional Geometry
The refractive index for a prism is given as
μ
=
cot
A
2
\mu = \cot \frac{A}{2}
μ
=
cot
2
A
. Then, angle of minimum deviation in terms of angle of prism is
VITEEE - 2015
VITEEE
Physics
Refraction of Light
If
∣
z
∣
≥
3
|z| \ge 3
∣
z
∣
≥
3
, then the least value of
∣
z
+
1
4
∣
\left|z+\frac{1}{4}\right|
z
+
4
1
is
VITEEE - 2015
VITEEE
Mathematics
complex numbers
The masses of three copper wires are in the ratio
2
:
3
:
5
2 : 3 : 5
2
:
3
:
5
and their lengths are in the ratio
5
:
3
:
2
5 : 3 : 2
5
:
3
:
2
.Then, the ratio of their electrical resistances is
VITEEE - 2015
VITEEE
Physics
Resistance
On the interval
[
0
,
1
]
[0, 1]
[
0
,
1
]
, the function
x
25
(
1
−
x
)
75
x^{25}(1 - x)^{75}
x
25
(
1
−
x
)
75
takes its maximum value at the point
VITEEE - 2015
VITEEE
Mathematics
Application of derivatives
Point out incorrect stability order
VITEEE - 2015
VITEEE
Chemistry
Isomerism
In a potentiometer experiment, the balancing length of a cell is
560
c
m
560\, cm
560
c
m
. When an external resistance of
10
Ω
10 \, \Omega
10
Ω
is connected in parallel to the cell, the balancing length changes by
60
c
m
60 \,cm
60
c
m
.The internal resistance of a cell is
VITEEE - 2015
VITEEE
Physics
Magnetic Field
The molarity of
N
O
3
−
NO_3^-
N
O
3
−
in the solution after
2
L
2L
2
L
of
3
M
A
g
N
O
3
3M \, AgNO_3
3
M
A
g
N
O
3
is mixed with
3
L
3L
3
L
of
1
M
B
a
C
l
2
1M \, BaCl_2
1
M
B
a
C
l
2
is
VITEEE - 2015
VITEEE
Chemistry
Expressing Concentration of Solutions
The chemical composition of slag formed during the smelting process in the extraction of copper is
VITEEE - 2015
VITEEE
Chemistry
Refining
If line
y
=
2
x
+
c
y = 2\,x + c
y
=
2
x
+
c
is a normal to the ellipse
x
2
9
+
y
2
16
=
1
\frac{x^2}{9} + \frac{y^2}{16} = 1
9
x
2
+
16
y
2
=
1
, then
VITEEE - 2015
VITEEE
Mathematics
Ellipse
The area bounded by the curves
y
=
c
o
s
x
y = cos\, x
y
=
cos
x
and
y
=
s
i
n
x
y = sin \,x
y
=
s
in
x
between the ordinates
x
=
0
x = 0
x
=
0
and
x
=
3
π
2
x = \frac{3\pi}{2}
x
=
2
3
π
is
VITEEE - 2015
VITEEE
Mathematics
Integrals of Some Particular Functions
The normal at the point
(
a
t
1
2
,
2
a
t
1
)
(at_1^2 ,\, 2at_1)
(
a
t
1
2
,
2
a
t
1
)
on the parabola meets the parabola again in the point
(
a
t
1
2
,
2
a
t
2
)
(at_1^2 ,\, 2at_2)
(
a
t
1
2
,
2
a
t
2
)
, then
VITEEE - 2015
VITEEE
Mathematics
Parabola
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