>
Exams
>
Mathematics
>
Sets
>
if a 1 2 3 b 3 4 then a cup b is
Question:
If \(A=\{1,2,3\}\), \(B=\{3,4\}\), then \(A\cup B\) is:
Show Hint
Union combines all unique elements.
VITEEE - 2025
VITEEE
Updated On:
Jan 5, 2026
\{1,2\}
\{3\}
\{1,2,3,4\}
\{1,2,3\}
Hide Solution
Verified By Collegedunia
The Correct Option is
C
Solution and Explanation
Union contains all distinct elements of both sets.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Sets
If $A = \{x \in \mathbb{R} \mid \sin^{-1}(\sqrt{x^2+x+1}) \in [-\frac{\pi}{2}, \frac{\pi}{2}]\}$ and $B = \{y \in \mathbb{R} \mid y = \sin^{-1}(\sqrt{x^2+x+1}), x \in A\}$, then
AP EAPCET - 2025
Mathematics
Sets
View Solution
Given the sets $ A = \{ x \mid |x - 2|<3 \} $ and $ B = \{ x \mid |x + 1| \leq 4 \} $, find $ A \cap B $.
BITSAT - 2025
Mathematics
Sets
View Solution
The distance of the point \( (2, 3) \) from the line \( 2x - 3y + 28 = 0 \), measured parallel to the line \( \sqrt{3}x - y + 1 = 0 \), is equal to
JEE Main - 2024
Mathematics
Sets
View Solution
The equation of a common tangent to the parabolas \( y = x^2 \) and \( y = -(x - 2)^2 \) is:
VITEEE - 2024
Mathematics
Sets
View Solution
If \[ S(x) = (1 + x) + 2(1 + x)^2 + 3(1 + x)^3 + \ldots + 60(1 + x)^{60}, \, x \neq 0, \] and \[ (60)^2 S(60) = a(b)^b + b, \] where $a, b \in \mathbb{N}$, then $(a + b)$ is equal to ________.
JEE Main - 2024
Mathematics
Sets
View Solution
View More Questions
Questions Asked in VITEEE exam
The coordination number and geometry of \([\mathrm{Ni(CN)_4
]^{2-}\) and \([\mathrm{NiCl_4}]^{2-}\) are respectively:}
VITEEE - 2025
coordination compounds
View Solution
The IUPAC name of \([\mathrm{Co(NH_3)_5Cl}]\mathrm{SO_4}\) is:
VITEEE - 2025
coordination compounds
View Solution
Which of the following compounds will show geometrical isomerism?
VITEEE - 2025
coordination compounds
View Solution
Which of the following is a characteristic property of acids?
VITEEE - 2025
Acids and Bases
View Solution
Which of the following is an example of an exothermic reaction?
VITEEE - 2025
Acids and Bases
View Solution
View More Questions