Question:
The value of \( \int_0^{\pi/2} \sin^2 x \, dx \) is:
The value of \( \int_0^{\pi/2} \sin^2 x \, dx \) is:
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Use identity \(\sin^2x = \frac{1-\cos2x}{2}\).
Updated On: Jan 5, 2026
- \(\pi/4\)
- \(\pi/2\)
- 1
- \(\pi\)
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The Correct Option is A
Solution and Explanation
\[
\int_0^{\pi/2} \sin^2x dx = \frac{\pi}{4}
\]
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