List of top Questions asked in VITEEE

The moment about the point \( 2i + 3j + k \) of a force represented by \( i + j + k \) acting through the point \( 2i + 3j + k \) is

The equation of one of the common tangents to the parabola \( y^2 = 8x \) and \( x^2 = 4y - 4 \) is

The distance moved by the particle in time \( t \) is given by \[ s = t^3 - 12t^2 + 6t + 8 \] At the instant, when its acceleration is zero, its velocity is

The equation of one of the common tangents to the parabola \( y^2 = 8x \) and \( x^2 = 4y - 4 \) is

If the tangent to the function \( y = f(x) \) at \( (3, 4) \) makes an angle of \( \frac{3\pi}{4} \) with the positive direction of the x-axis in anticlockwise direction, then \( f'(3) \) is

The probability of India winning a test match against Australia is \( \frac{1}{2} \), assuming independence from match to match. The probability that in a match series India’s second win occurs at third test match is

The following data were obtained for a given reaction at 300 K. \[ \begin{array}{|c|c|} \hline \text{Reaction} & \text{Energy of activation (kJ mol}^{-1}\text{)} \\ \hline \text{(i) Uncatalysed} & 76 \\ \text{(ii) Catalysed} & 57 \\ \hline \end{array} \] The factor by which the rate of catalysed reaction is increased is

The foci of the ellipse \( \frac{x^2}{144} + \frac{y^2}{81} = 1 \) and the hyperbola \( \frac{x^2}{144} - \frac{y^2}{81} = 1 \) coincide then value of \( b^2 \) is

Which of the following reactions of xenon compounds is not feasible?

Anisole is treated with HI under two different conditions. \[ C_6H_5OCH_3 + D \xrightarrow{\text{conc. HI}} A + B \] The nature of A and B will be

Phenol undergoes electrophilic substitution more easily than benzene because

Which of the following name reaction is not used for introducing a \( \text{-COOH} \) group?

Esterification of acid chloride with ethanol is usually carried out in the presence of pyridine. The function of pyridine is

The solution of the differential equation \[ (1 + y^2) + (x - e^{\tan^{-1}y}) \frac{dy}{dx} = 0 \] is

A tetrahedron has vertices at \( O(0,0,0), A(1,2,1), B(2,1,3) \) and \( C(-1,1,2) \). Then the angle between the faces \( OAB \) and \( ABC \) will be

The enthalpy change for a given reaction at 298 K is \( -x \, \text{J mol}^{-1} \). For the reaction to be spontaneous at 298 K, the entropy change at that temperature

\( a \) moles of \( \text{PCl}_5 \) is heated in a closed container to equilibrate \[ \text{PCl}_5 (g) \rightleftharpoons \text{PCl}_3 (g) + \text{Cl}_2 (g) \] at a pressure of \( P \) atm. If \( x \) moles of \( \text{PCl}_5 \) dissociate at equilibrium, then the correct expression for the equilibrium constant is

A plot of \( \ln K \) against \( 1/T \) (abscissa) is expected to be a straight line with intercept on ordinate axis equal to

In a reaction \( A \to \) Products, when start is made from \( 8.0 \times 10^{-2} \) M of A, half-life is found to be 120 minutes. For the initial concentration \( 4.0 \times 10^{-2} \) M, the half-life of the reaction becomes 240 minutes. The order of the reaction is:

A reaction \( A_2 + B \to \) Products, involves the following mechanism: \[ A_2 \rightleftharpoons 2A \text{ (fast)} \quad \text{(A being the intermediate)} \] \[ A + B \xrightarrow{k_2} \text{ Products (slow)}. \] The rate law consistent to this mechanism is:

The wave number of the first emission line in the Balmer series of H-Spectrum is: \[ (R = \text{Rydberg constant}) \]

If the reaction \( \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \) occurs at 200°C and 1000 atm then the graph showing the correct equilibrium yield at 400°C is

Group 15 elements have more electron gain enthalpy than group 16 elements. The correct reason for this is

\( \text{t-butyl} - \text{CH}_3 \text{C} - \text{CH}_2 \text{OH} \) can’t give decarboxylation while normally \( \alpha-\beta \) unsaturated acid give this reaction because

Which type of carbocation is/are formed when \( \text{OH} \) is treated with an acid?