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VITEEE
List of top Questions asked in VITEEE
Let A be the centre of the circle $x^{2}+y^{2}-2x-4y-20=0,$ and B( 1,7) andD(4,-2) are points on the circle then, if tangents be drawn at B and D, which meet at C, then area of quadri 1 ateral A BCD is-
VITEEE - 2017
VITEEE
Mathematics
Circle
If the eccentricity of the hyperbola $x^{2}-y^{2} cos ec^{2} \alpha=25 is \sqrt{5}$ times the eccentricity of the ellipse $x^{2} cos ec^{2} \alpha+y^{2}=5, then \alpha$ is equal to :
VITEEE - 2017
VITEEE
Mathematics
Hyperbola
A plot of ln K against $\frac{1}{T}$ (abscissa) is expected to be a straight line with intercept on ordinate axis equal
VITEEE - 2016
VITEEE
Chemistry
Thermodynamics
Which of the two acids form anhydrides? (I) Oxalic acid (II) Succinic acid (III) Benzoic acid (IV) Phthalic acid
VITEEE - 2016
VITEEE
Chemistry
Acids and Bases
Anisole is treated with HI under two different conditions.
$\ce{ C + D [conc.HI] A + B }$
The nature of A to D will be
VITEEE - 2016
VITEEE
Chemistry
Chemical Reactions
In given circuit, all resistances are of
$10 \Omega$
. Current flowing through ammeter is
VITEEE - 2016
VITEEE
Physics
Resistance
Which statement is correct for the given circuit?
VITEEE - 2016
VITEEE
Physics
Resistance
Two solenoids are given - 1st has 1 turn per unit length and 2nd has n turns per unit length. Ratio of magnetic fields at their centres is
VITEEE - 2016
VITEEE
Physics
Magnetic Field
A (+)vely charged particle is placed near an infinitely long straight conductor where there is zero gravity. Then
VITEEE - 2016
VITEEE
Physics
Magnetic Field Due To A Current Element, Biot-Savart Law
The probability of India winning a test match against Australia is $\frac{1}{2}$ assuming independence from match to match. The probability that in a match series India�s second win occurs at third test match is
VITEEE - 2016
VITEEE
Mathematics
Probability
If
$g(x)$
is a polynomial satisfying
$g (x) g(y) = g(x) + g(y) + g(xy) - 2 $
for all real
$x$
and
$y$
and
$g (2) = 5$
then
$\Lt_{x \to 3} g(x)$
is
VITEEE - 2016
VITEEE
Mathematics
solution of system of linear inequalities in two variables
If $g(x)$ is a polynomial satisfying $g (x) g(y) = g(x) + g(y) + g(xy) - 2 $ for all real $x$ and $y$ and $g (2) = 5$ then $\Lt_{x \to 3} g(x)$ is
VITEEE - 2016
VITEEE
Mathematics
solution of system of linear inequalities in two variables
The wavenumber of the first emission line in the Balmer series of H-Spectrum is: [$R=$ Rydberg constant]
VITEEE - 2016
VITEEE
Chemistry
Bohr’s Model for Hydrogen Atom
Among the following the incorrect statement is
VITEEE - 2016
VITEEE
Chemistry
Chemical Kinetics
Which one of the following reactions of xenon compounds is not feasible?
VITEEE - 2016
VITEEE
Chemistry
Group 18 Elements
For hydrogen-oxygen fuel cell, the cell reaction is
\(2H_2(g)+O_2(g)\rightarrow2H_2O(I)\)
, If
\(\triangle{G}\degree_{f}(H_2O)=-237.2KJmol^{-1}\)
then emf ofthis cell is
VITEEE - 2016
VITEEE
Chemistry
Gibbs Free Energy
IUPAC name of valeric acid is
VITEEE - 2016
VITEEE
Chemistry
Aldehydes, Ketones and Carboxylic Acids
An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be
VITEEE - 2016
VITEEE
Chemistry
Unit Cells
One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litres. Then
$ {\Delta S (cal \, deg^{-1} \, mol^{-1})}$
for this process is :
$ { (R = 2 \, cal \, K^{-1} \, mol^{-1})}$
VITEEE - 2016
VITEEE
Chemistry
internal energy
The protein present in the hair is
VITEEE - 2016
VITEEE
Chemistry
Proteins
Phenol undergoes electrophilic substitution more easily than benzene because
VITEEE - 2016
VITEEE
Chemistry
Alcohols, Phenols and Ethers
Esterification of acid chloride with ethanol is usually carried out in the presence of pyridine. The function of pyridine is
VITEEE - 2016
VITEEE
Chemistry
Organic Chemistry
Group 15 elements have more electron gain enthalpy than group 16-elements. The correct reason for this is
VITEEE - 2016
VITEEE
Chemistry
Group 15 Elements
Two point dipoles $p \hat{k}$ and $\frac{p}{2} \hat{k}$ are located at $(0,0,0)$ and $(1\, m , 0,2\, m )$ respectively. The resultant electric field due to the two dipoles at the point $(1 \,m , 0,0)$ is
VITEEE - 2016
VITEEE
Physics
Electric Dipole
A square current carrying loop is changed to a circular loop in time
$t_1$
. Then
VITEEE - 2016
VITEEE
Physics
Inductance
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