List of top Mathematics Questions asked in SRMJEEE

y x is normal variate such that mx(t)=e3+8+2,then the varience is 

if x\(\neq\)y\(\neq\)z and \(\begin{vmatrix} x&x^2&1+x^3 \\  y&y^2&1+y^3 \\  z&z^2&1+z^3  \end{vmatrix}=0\), then the value of xyz is_________
the value of ∫\(\frac{dx}{x(1+log\,x)^3}\) is _______

Evaluate ∫cos2 xdx_________

The equation of the straight line which passes through the point (-5,4) and is such that the position of it between them is divided by the given point in the ratio 1:2: is_____.

The value of \(lim x.sin \frac {2}{x}\) is__________.

What can be said regarding a line if its slope is negative?

The value of √(-25)+3√(-4)+2√(-9) is __________
What can be said regarding a line if its slope is negative?
If the pth, qth, rth terms of an A.P are in G.P, then the common ratio of the G.P is
Find the 4th term in the expansion of (-3a - b)5
In a G.P if the (m+n)th term is p and (m-n)th term is q then its mth term is
If the circles x2 + y2 + 2x + 2ky + 6 = 0, x2 + y2 + 2ky + k = 0 intersect orthogonally, then k is
A box contains 5 red and 4 white balls. Two balls are drawn successively from the box without replacement and it is noted that the second one is white. Then the probability that the first one is white is
If a,b,c are in AP, then a3+c3-8b3 is equal to
Consider points A,B,C and D with position vectors \(7\vec{i}-4\vec{j}+7\vec{k}, \vec{i}-6\vec{j}+10\vec{k}, -\vec{i}-3\vec{j}+4\vec{k}\) and \(5\vec{i}-\vec{j}+5\vec{k}\) respectively, then ABCD is a
The centre and radius of the sphere \(|2\vec{r}=(J\vec{i}-\vec{j}+4\vec{k})|=4\) are __________
The coefficient of skewnes of a distribution is 0.32. If its standard deviation is 6.5 and mean is 29.6, then the mode of the distribution is given by
The equation of the second degree x2+2√2xy+2y2+4x+4√2y+1=0 represents a pair of straight lines, the distance between them is
\(\displaystyle\int\frac{dx}{cosx-sinx}\) is equal to
The value of the integral \(\int\limits^6_3\frac{\sqrt{x}}{\sqrt{9-x}+\sqrt x}dx\) is
\(\int \sec xdx\) is
The line 4x+6y+9=0 touches y2=4x at the point
ABCD is a square A = (1,2), B = (3,-4). If line CD passes through (3,8) then midpoint of CD is
The circles x2 + y2 - 4x - 6y - 12 = 0 and x2 + y2 + 6x - 8y + 21 = 0