To find the particular integral of the differential equation \((D^2 - 3D + 2)y = e^{3x}\), we'll use the method of undetermined coefficients.
1. Given Differential Equation:
\[ (D^2 - 3D + 2)y = e^{3x} \] where \( D = \frac{d}{dx} \).
2. Find the Particular Integral (P.I.):
For an exponential forcing function \( e^{ax} \), the P.I. is given by: \[ \text{P.I.} = \frac{1}{f(D)} e^{ax} = \frac{1}{f(a)} e^{ax} \quad \text{if} \quad f(a) \neq 0 \] Here, \( f(D) = D^2 - 3D + 2 \) and \( a = 3 \).
3. Evaluate \( f(3) \):
\[ f(3) = (3)^2 - 3(3) + 2 = 9 - 9 + 2 = 2 \neq 0 \]
4. Compute the Particular Integral:
Since \( f(3) = 2 \neq 0 \), we have: \[ \text{P.I.} = \frac{1}{D^2 - 3D + 2} e^{3x} = \frac{1}{2} e^{3x} \]
5. Verification:
Let's verify by substituting \( y_p = \frac{1}{2} e^{3x} \) back into the differential equation: \[ (D^2 - 3D + 2)\left(\frac{1}{2} e^{3x}\right) = \frac{1}{2} (9 - 9 + 2) e^{3x} = e^{3x} \] which matches the right-hand side of the original equation.
6. Comparing with Given Options:
The correct particular integral is: \[ e^{3x} \]
Final Answer:
The particular integral is \(\boxed{e^{3x}}\).
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely