Question:
The value of the integral \(\int\limits^6_3\frac{\sqrt{x}}{\sqrt{9-x}+\sqrt x}dx\) is
The value of the integral \(\int\limits^6_3\frac{\sqrt{x}}{\sqrt{9-x}+\sqrt x}dx\) is
Updated On: Oct 4, 2024
- \(\frac{3}{2}\)
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- 1
- \(\frac{1}{2}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{3}{2}\)
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